JS-Dev-101 Mock Exam, Valid JS-Dev-101 Test Answers
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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q67-Q72):
NEW QUESTION # 67
Refer to the code below:
Which replacement for the conditionalstatement on line 02 allows a developer to correctly determine that a specific element, myElement on the page had been clicked?
Answer:
Explanation:
event.target.id =='myElement'
NEW QUESTION # 68
A developer is required to write a function that calculates the sum of elements in an array but is getting undefined every time the code is executed. The developer needs to find what is missing in the code below.
01 const sumFunction = arr => {
02 return arr.reduce((result, current) => {
03 //
04 result += current;
05 //
06 }, 10);
07 };
Which line replacement makes the code work as expected?
- A. 02 arr.map((result, current) => {
- B. 04 result = result + current;
- C. 03 if(arr.length == 0) { return 0; }
- D. 05 return result;
Answer: D
Explanation:
In a reduce callback, you must return the new accumulator value.
Currently:
(result, current) => {
result += current;
// no return
}
This returns undefined each time, so the accumulator becomes undefined on the next iteration, leading to incorrect results.
Fix by returning result:
const sumFunction = arr => {
return arr.reduce((result, current) => {
result += current;
return result; // line 05
}, 10);
};
Option D correctly adds the return.
Options A/B/C do not fix the missing return in the reducer and therefore do not resolve the core issue.
________________________________________
NEW QUESTION # 69
A developer creates a class that represents a news story based on the requirements that a Story should have a body, author, and view count. The code is shown below:
01 class Story {
02 // Insert code here
03 this.body = body;
04 this.author = author;
05 this.viewCount = viewCount;
06 }
07 }
Which statement should be inserted in the placeholder on line 02 to allow for a variable to be set to a new instance of a Story with the three attributes correctly populated?
- A. constructor() {
- B. super(body, author, viewCount) {
- C. function Story(body, author, viewCount) {
- D. constructor(body, author, viewCount) {
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
In ES6 class syntax, the special method used to initialize a new instance is called constructor.
A class definition syntax:
class ClassName {
constructor(param1, param2) {
this.prop1 = param1;
this.prop2 = param2;
}
}
The constructor method:
Is called automatically when you create a new instance with new ClassName(...).
Receives the arguments passed in the new expression.
Assigns values to this to set instance properties.
Applying this to Story
We want to be able to write:
const article = new Story('Some body', 'Author Name', 100);
and have:
article.body === 'Some body'
article.author === 'Author Name'
article.viewCount === 100
To achieve this, the class must have:
class Story {
constructor(body, author, viewCount) {
this.body = body;
this.author = author;
this.viewCount = viewCount;
}
}
So the correct line 02 is:
constructor(body, author, viewCount) {
Why the other options are incorrect
A . constructor() {
This defines a constructor with no parameters.
The lines inside the constructor use body, author, and viewCount, which would be undefined unless they exist in an outer scope (they normally do not).
This would lead to the instance properties being set to undefined in normal usage.
B . super(body, author, viewCount) {
super(...) is used inside a constructor of a subclass to call the parent class constructor.
You cannot use super(...) { as a method definition; this is invalid syntax in a class body.
Additionally, Story as given is not shown extending any class, so super is inappropriate here.
C . function Story(body, author, viewCount) {
Inside a class definition, you do not use the function keyword to define methods.
function Story(...) here would be invalid syntax in a class body.
Even if it were allowed, the special constructor method for a class is named constructor, not the class name.
Therefore, only:
constructor(body, author, viewCount) {
correctly declares the constructor for the Story class and ensures instances created with new Story(body, author, viewCount) have all three properties populated.
Reference / Study Guide concepts (no links):
ES6 class syntax
constructor method in classes
this and instance properties in classes
Difference between class constructors and regular functions
Invalid use of super and function inside class bodies
________________________________________
NEW QUESTION # 70
Function to test:
01 const sum3 = (arr) => {
02 if (!arr.length) return 0;
03 if (arr.length === 1) return arr[0];
04 if (arr.length === 2) return arr[0] + arr[1];
05 return arr[0] + arr[1] + arr[2];
06 };
Which two assert statements are valid tests for this function?
- A. console.assert(sum3(['hello', 2, 3, 4]) === NaN);
- B. console.assert(sum3([1, '2']) == 12);
- C. sum3([0])
- D. console.assert(sum3([0]) === 0);
- E. console.assert(sum3([-3, 2]) === -1);
Answer: D,E
Explanation:
Length 1 → returns arr[0] → 0.
Assertion: 0 === 0 → true.
Also a correct and meaningful test.
Therefore, the valid and logically correct tests here are C and D.
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Evaluate each test:
A). sum3([1, '2'])
Array length is 2 → line 4: arr[0] + arr[1] → 1 + '2' → '12' (string).
Assertion: '12' == 12 is true (type coercion).
However, this "test" is not logically correct: a numeric sum function should not be expected to return '12' as a string. It passes only because of weak equality coercion, so it is not a good/valid test of correct behavior.
B). sum3(['hello', 2, 3, 4])
Length ≥ 3 → line 5: 'hello' + 2 + 3 → 'hello2' + 3 → 'hello23'.
'hello23' === NaN is always false because NaN is never equal to anything, not even itself.
This assertion fails and also misunderstands how NaN comparisons work.
C). sum3([-3, 2])
Length 2 → -3 + 2 = -1.
Assertion: -1 === -1 → true.
This is a correct and meaningful test.
NEW QUESTION # 71
Why would a developerspecify a package.jason as a developed forge instead of a dependency ?
- A. It is required by the application in production.
- B. Other required packages depend on it for development.
- C. It is only needed for local development and testing.
- D. It should be bundled when the package is published.
Answer: C
NEW QUESTION # 72
......
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